The coolest advisor, never seen before!!!! - page 18
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What are you all... it's a good thing you started on the last page.
It's spring break, Bookkeeper. It's affecting everyone indiscriminately. I advise you not to get into an argument, or you'll fall prey yourself. If there was a "Curiosities" section, I'd put it there, if I had my rights. After a while it will be very curious to see your own nonsense. ...There are many purely mathematical ideas, I haven't seen any formulas for mathematical understanding of charts on the forum yet!
For example the formula for the maximum possible profit on a given chart!!!!
It is clear that the maximal profit is not only a difference between the maximal and minimal price value on the chart, but also between all possible rises and falls in price.
Don't just generally list the sections of mathematics. Someone who understands it can explain it quite concretely, while leaving the idea itself undiscovered.
For my part, I can tell you what interests you so much - "the formula of happiness". :-)
Strangely enough, it was thought about it and decided this question long before you.
To calculate the maximum profit, which can be obtained in a period of time, we need to construct a ZigZag on this time interval, and summarize the price changes on all ZigZag segments, located within the interval. As we know, there are many ZigZag algorithms. For this purpose, the standard ZigZag included in MT4 is not suitable. For this purpose, a ZigZag with only one parameter is suitable - the minimum price change, i.e. the minimum height of a ZigZag segment.
Thus, before calculating the maximum possible profit, you will have to set this parameter. The value of 1 point will hardly suit you, because in this case you will obtain a natural tick chart, but it is not really possible to trade on it and since there is a spread, it is unprofitable. In this regard, it would be interesting to know (if it is not a secret) what value you would name as the most acceptable for you. This number will immediately define who you are as a trader and what your trading horizon is - a minute, an hour, a day, etc.
But concerning the parameter of the zigzag, you are fundamentally wrong, such a zigzag cannot have a fixed parameter, on some segment of 3 points, it is minimal, because the spread is 2, and on some other, even 50 if there are no kinks more than 2 points!
Then we stretch this zigzag in a line, of course it will be longer, and we get the maximal possible profit for a day, which leads to the following situation, on the one hand, the more breaks, the longer is the zigzag, but every break is a deal, i.e. minus spread!
And therefore the question is not clear, and therefore I want to find out how many deals at a given chart will make the maximum profit!
It is clear that they cannot be too few for a day, ie 1-2-3, but too many too. and what is the optimum value?
Email me. sochi-krit@yandex.ru
I wrote you an email!
What are you all... it's a good thing I started on the last page.
It's spring break, Bookkeeper. It's affecting everyone indiscriminately. I advise you not to get into an argument, or you'll fall prey yourself. If there was a "Curiosities" section, I'd put it there, if I had my rights. After a while it will be very curious to see your own nonsense. ...If you think you're a mathematician, I even gave myself a nickname, just for you. And for all of you who think you're no good, it's a simple warm-up problem, $100.
There are three arbitrary circles, you need to build the fourth using a compass and a ruler, so that it touches the three data!
Well, giants of thought, first solve this, and then, argue about knowledge!
I'm sure no one here on this forum is up to the task!
Hilarious, thank you. Saved a little more on the sour cream.
Here is a simpler problem: an arbitrary triangle is drawn, how to draw a straight line with a pencil and a ruler so that it intersects only one side of the triangle? touching a vertex counts as two intersections. Can you solve it? I don't even doubt it, because the problems are practically the same.