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Go ahead and blurt it out then. Write your whole reasoning for three cubes.
Для трех кубиков вероятность выпадения хотя-бы одной шестерки равна 1-вероятность ее невыпадения
For now.
Go ahead and blurt it out then. Write your whole reasoning for three cubes.
For now.
I can do it for 300cc as well :)
Alexei, this is no longer a probability, but a mathematical expectation :(
I threw (I mean threw a die) - one outcome. I threw another one, then another... You can roll all at once - no difference...
So far, so good. Next...
So you turn a single roll of 4 dice into a series of 4 rolls with p = 1/6? (CHUCKLES) OKAY.
Okay, I get it. Same Bernoulli series. And the answer is the same as mine :)
Criticise, don't criticise: the probability of a six is 1/6. For four independent throws the expectation of winning = 4*1/6=2/3. If all four throws occur simultaneously, the situation does not change
In short, the probability of the final event in this case is a false concept, like centrifugal force :)
Короче, вероятность итогового события в данном случае - ложное понятие, наподобие центробежной силы :)
Ah, I see. So you're saying that by rolling 4 dice a billion times, we don't get some measure of the "at least one 6 fell" event close to a theoretical value?