Pure maths, physics, logic (braingames.ru): non-trade-related brain games - page 216

 

Two people play the following game. An even number of number cards are laid out in a row on the table. Players take turns picking one of the cards from either end of the row. Whoever wins has to get the higher amount, otherwise it's a draw. Who does not lose in this game? What is the non-losing strategy?

The challenge is here. The weight is 5.

FAQ:

- don't be intimidated by the weight, it's uncomplicated (as I understand it, the weight is calculated from the ratio of the number of people who saw the problem to those who solved it),

- The numbers are all real. Some may be the same,

- you have to come up with a non-win strategy.

Задачи, загадки, логические игры [Игры разума] икф
  • www.braingames.ru
Двое играют в следующую игру. На столе в ряд выложено четное число карточек с числами. Игроки по очереди берут одну из карточек с любого из концов ряда. Выигравший должен набрать бОльшую сумму, иначе ничья. Кто не проигрывает в этой игре? Какова непроигрышная стратегия?
 
Mathemat:

Two people play the following game. An even number of number cards are laid out in a row on the table. Players take turns picking one of the cards from either end of the row. Whoever wins has to get the higher amount, otherwise it's a draw.

Who does not lose in this game?

What is the non-losing strategy?

/There was an absolutely correct decision, which has been deleted - Mathemat/.

Amen.

 
Mathemat:

Two people play the following game. An even number of number cards are laid out in a row on the table. Players take turns picking one of the cards from either end of the row. Whoever wins has to get the higher amount, otherwise it's a draw. Who does not lose in this game? What is the non-losing strategy?

The challenge is here. The weight is 5.

FAQ:

- don't be intimidated by the weight, it's uncomplicated (as I understand it, the weight is calculated from the ratio of the number of people who saw the problem to those who solved it),

- The numbers are all real. Some may be the same,

- you have to come up with a non-win strategy.

The game consists of only one approach? I.e. everyone took one picture and counted the result?

 
barabashkakvn:

Does the game consist of only one approach? I.e. everyone took one picture and counted the result?

No, not from one approach. All the cards must be chosen.
 
Mathemat:

Two people play the following game. An even number of number cards are laid out in a row on the table. Players take turns picking one of the cards from either end of the row. Whoever wins has to get the higher amount, otherwise it's a draw. Who does not lose in this game? What is the non-losing strategy?

The challenge is here. The weight is 5.

FAQ:

- don't be intimidated by the weight, it's uncomplicated (as I understand it, the weight is calculated from the ratio of the number of people who saw the problem to those who solved it),

- The numbers are all real. Some may be the same,

- you have to come up with a non-win strategy.

Take the last card with the highest number, of course the one who takes it first wins, if he counts well.)
 
sanyooooook:
The last card with the highest number wins, of course, if it counts well.)
So are the cards face down or what?
 
barabashkakvn:
So the cards are face down, are they?
so it looks like it is))
 
The strategy is to go first
 
Take a card whose difference with the next one is disadvantageous to the opponent. And go first.
 
TheXpert:
Taking a card whose difference with the next is disadvantageous to the opponent.

You're only looking 1-2 moves ahead. And there are a lot of cards, like 100 cards, for example.

And walk first.

Why go first? The second is not stupider, by the way.

Barabashkakvn:
The strategy is to go first.
Justify.