Pure maths, physics, logic (braingames.ru): non-trade-related brain games - page 110
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OK, let the pole consist of a thousand bricks. Can you solve it for that height?
OK, let the column consist of one thousand bricks. Can you solve it for this height?
Let's try this. Let's say that the pole is solid and stands upright. Its centre of gravity will be in the middle.
Now shift all the bricks so that the uppermost brick is shifted by a full width relative to the lowest one.
The centre of gravity is now half a brick to the left of the lowest brick.
Conclusion: such a post will stand as long as its centre of gravity is no further than one of the boundaries of the base (the lowest brick).
Yes, it turns out as in the first solution, the answer is correct. Or not. I'm confused.
so the same thing - half a brick // that's why you brought up muzik ))
Nah. Mucik he remembered because it's not half a brick, but a brick.
Because the solution is very similar, the same law comes out there.
Nah. He remembered Muzik because it's not half a brick, it's a brick.
Shit, maybe it's a brick. When the number of bricks tends to infinity
Where am I gonna find so many bricks at 2:30 in the morning, huh?)
The problem does not seem to have an explicit solution, because the condition is not explicit.