NormalizeDouble rounding ? - page 2

 

Okay I let that here, it can be called like the classical normalizedouble

double NormalizeNoRound(double x, int digits) {
   return(StringToDouble(StringSubstr(DoubleToString(x,digits+1),0,StringLen(DoubleToString(x,digits+1))-1)));
}

edit : 

double NormalizeNoRound(double x, int digits) {
   return(MathFloor(x*MathPow(10,digits))/MathPow(10,digits));
}