Any questions from newcomers on MQL4 and MQL5, help and discussion on algorithms and codes - page 1839
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Good afternoon!!! Happy New Year everyone!!!
Water code removing horizontal line
Thanks for the help.
This is more than enough.
The question is very simple you need to know the coordinates of the inscription with reference to the horizontal line as I do not know how to calculate it.
Here you can help
ChartTimePriceToXY
ChartXYToTimePrice
That's more than enough.
Here's where you can get help.
ChartTimePriceToXY
ChartXYToTimePrice
Thanks for the tip Rostislav, but I'm doing something wrong.
I need to change only the 0Y axis, but the inscription does not want to marry with the horizontal line.
I am attaching code and screenshot please advise where is the error?
Thanks for the tip, Rostislav, but I'm doing something wrong.
I need to change only the 0Y axis, but the inscription does not want to marry with the horizontal line.
I am attaching the code and a screenshot, can you tell me where the error is?
Don't forget the brackets.
Don't forget the brackets.
No, there's something else missing.
No, something else is missing
Copying to an array
How do I get the maximum high in an array?
Copying to an array
How to get the maximal high in an array?
Additionally copy CopyHigh and get the maximal from this array. I understand that through ...it... but the only other way is to try over in the loop.
Additionally copy CopyHigh and get maximal from this array. I understand that through ...it... but the other option is only looping.
I did so, but it is additional copying. Using a loop is also not an option.
I'll leave it withCopyHigh.
I did, but it's an extra copy. Through the loop is not an option either.
I'll leave it throughCopyHigh then.
I've been thinking about it for a long time. And I've come to the conclusion, that if we need to look for minimum/maximum from MqlRates array, it's better to copy required data to different double arrays.
Copying to an array
How do I get the maximum high in an array?