Can you write code to delete all pending orders? - MQL4 and MetaTrader 4

zsu1970 2017.02.27 13:14 #1341

Vitaly Muzichenko:
Do you put the prices in all at once, or do you get them and then put them in the calculation?

Vitaly Muzichenko:
Do you set the prices at once, or get them and then paste them into calculation?

int k=period;
for(int i=1; i<=period; i++)
{
H1_Close[i]=Close[k];
k--;
}
I take a chunk of timesession equal to the period starting from the last closed bar and flip it over in the array, because 1 is the penultimate bar in timesession and calculation must start from i-th
i.e. my function should return SMMA value of the last closed bar.

[Archive!] Ready to write Any rookie question, so Questions from Beginners MQL4

ANDREY 2017.02.27 13:17 #1342

Good afternoon, everyone.
The code below encodes a simple idea.
If the last closed order was on SEL
If the last closed order was on the NEL
Open a NEL order

if (OrderSelect (Ht-1,SELECT_BY_POS, MODE_HISTORY))
if ( OrderType ()==OP_SELL)
X = OrderProfit( );

if (OrderSelect (Ht-1,SELECT_BY_POS, MODE_HISTORY))
if ( OrderType ()==OP_BUY)
if(X < 0)

OrderSend(Symbol(),OP_SELL,0.1,Bid ,3,Ask+400*Point,Ask-200*Point,"17-10",123 );

QUESTION
What language construct can be used to add two more conditions to this code (circled in red)

If the last closed order is NEL
If the last CEL order closed
If the last closed order has closed on the NEL
If the last closed order has been closed on aSL

Thank you for your help.

I would be very grateful if you could write the code and not just explain what has to be done.

Questions from Beginners MQL5 Any rookie question, so Looking for the last

0B53RV3R 2017.02.27 14:12 #1343

Hello. I am writing a script to delete all pending orders. However, it only deletes one order. I always have two pending orders or one. In either case it only deletes one Buy Stop. To delete Sell Stop you have to run the script again, provided there are no other Buy Stop orders. Please advise where the error is.

void DeleteOrders()

{

int Total=OrdersTotal();

for(int i=0;i<Total;i++)

if(OrderSelect(i,SELECT_BY_POS))

{

int type=OrderType(), ticket=OrderTicket();

bool c;

switch(type)

{

case 4:

c=OrderDelete(ticket);

if(!c)

Print(GetLastError());

break;

case 5:

c=OrderDelete(ticket);

if(!c)

Print(GetLastError());

break;

}

close all pending orders MQL4 Learning Any rookie question, so

Maxim Kuznetsov 2017.02.27 14:18 #1344

0B53RV3R:
Hello. I am writing a script to delete all pending orders. However, it only deletes one order. I always have two pending orders or one. In either case it only deletes one Buy Stop. To delete Sell Stop you have to run the script again, provided there are no other Buy Stop orders. Please advise where the error is located.

void DeleteOrders()

{

int Total=OrdersTotal();

for(int i=0;i<Total;i++)

if(OrderSelect(i,SELECT_BY_POS))

{

int type=OrderType(), ticket=OrderTicket();

bool c;

switch(type)

{

case 4:

c=OrderDelete(ticket);

if(!c)

Print(GetLastError());

break;

case 5:

c=OrderDelete(ticket);

if(!c)

Print(GetLastError());

break;

}

Change the direction of the search for(i=total-1;i>=0;i--)

0B53RV3R 2017.02.27 14:48 #1345

Maxim Kuznetsov:
change the direction of the search for(i=total-1;i>=0;i--)

Thank you, now it works. Am I right to understand that when an order with index 0 is deleted, an order with index 1 is assigned index 0, and at the next iteration i == 1, and such an order does not exist. Can you tell me if this is the case?

[Archive!] Any rookie question, How to check if Any rookie question, so

Artyom Trishkin 2017.02.27 14:49 #1346

0B53RV3R:
Thank you, now it works. Do I understand correctly that when an order with index 0 is deleted, an order with index 1 is assigned index 0, and at the next iteration i == 1, and no such order appears. Can you tell if this is the case?

Right.

Vitaly Muzichenko 2017.03.03 03:57 #1347

There's a customisable fractal feature, well geez, that's awfully heavy. I've left the drawing of objects only to visually show if the fractals are forming correctly - it's not going to happen.

Question: how can we make it easier, because visual testing is stupid:

extern int FrLeft=15; // Баров слева
extern int FrRight=5; // Баров справа

//-----------------------------------------------------------------------------------------------
void OnTick()
{
int nFrUp= GetBarFractal(Symbol(),PERIOD_CURRENT,FrLeft,FrRight,0,MODE_UPPER); // Возвращает номер бара
int nFrDn= GetBarFractal(Symbol(),PERIOD_CURRENT,FrLeft,FrRight,0,MODE_LOWER); // Возвращает номер бара
double FrHigh = High[nFrUp]; // Цена верхнего фрактала
double FrLow  = Low [nFrDn]; // Цена нижнего фрактала

SetArrow("FrUp"+"_"+(string)Time[nFrUp], Time[nFrUp], High[nFrUp], clrDeepSkyBlue, 217, 2, ANCHOR_BOTTOM);
SetArrow("FrDn"+"_"+(string)Time[nFrDn], Time[nFrDn], Low[nFrDn], clrDeepPink, 218, 2, ANCHOR_TOP);

// Comment("Price: ",FrHigh,", Num: ",nFrUp,"\nPrice: ",FrLow,", Num: ",nFrDn);
}

//----------------------------------------------------------------------------------------------+
//---------------------- Возвращает номер бара фрактала (настраиваемый) ------------------------+
//----------------------------------------------------------------------------------------------+
int GetBarFractal(string symb,ENUM_TIMEFRAMES tf=0,int nLeft=2,int nRight=2,int numFr=0,int mode=MODE_UPPER) {
int i=0,cn=0,pos=0,r=0,l=0,e=0,equals,bars;
double _high[], _low[];
nLeft=nLeft<=2?2:nLeft;
nRight=nRight<=2?2:nRight;
equals=nLeft+nRight;
bars=Bars(symb,tf)-equals;
ArraySetAsSeries(_high,true);
ArraySetAsSeries(_low,true);

  for(pos=nRight+1; pos<bars; pos++) {
   r=nRight;
   if(mode==MODE_UPPER) {
    CopyHigh(symb,tf,0,pos+equals+1,_high);
    for(i=1; i<=r; i++) {
     if(_high[pos]<=_high[pos-i]) break;
   }}
   if(mode==MODE_LOWER) {
    CopyLow(symb,tf,0,pos+equals+1,_low);
    for(i=1; i<=r; i++) {
     if(_low[pos]>=_low[pos-i]) break;
   }}
   //--
   if(i==r+1) {
    l=nLeft;
    e=equals;
     for(int j=1; j<=l+equals; j++) {
      if(mode==MODE_UPPER) {
       if(_high[pos]<_high[pos+j])  break;
       if(_high[pos]>_high[pos+j])  l--;
       if(_high[pos]==_high[pos+j]) e--;
      }
      if(mode==MODE_LOWER) {
       if(_low[pos]>_low[pos+j])  break;
       if(_low[pos]<_low[pos+j])  l--;
       if(_low[pos]==_low[pos+j]) e--;
      }
      if(l==0) {
       cn++;
       if(cn>numFr) return(pos);
      }
      //--
      if(e<0) break;
   }}
  }
   Print(__FUNCTION__": Фрактал не найден");
  return(0);
}

//----------------------------------------------------------------------------------------------+
//------------------- Функция рисования значка на графике, объект OBJ_ARROW --------------------+
//----------------------------------------------------------------------------------------------+
void SetArrow(string nm="", datetime t1=0, double p1=0, color col=clrRed,
                                          int code=252, int width=1, int anchor=0) {
if(ObjectFind(0,nm)==-1) {
    ObjectCreate(0,nm,OBJ_ARROW,0,0,0);
    ObjectSetInteger(0,nm,OBJPROP_COLOR,col);
    ObjectSetInteger(0,nm,OBJPROP_ARROWCODE,code);
    ObjectSetInteger(0,nm,OBJPROP_ANCHOR,anchor);
    ObjectSetInteger(0,nm,OBJPROP_WIDTH,width);
    ObjectSetInteger(0,nm,OBJPROP_SELECTED,false);
    ObjectSetInteger(0,nm,OBJPROP_SELECTABLE,true);
    ObjectSetInteger(0,nm,OBJPROP_HIDDEN,false);
    ObjectSetDouble(0,nm,OBJPROP_PRICE,p1);
    ObjectSetInteger(0,nm,OBJPROP_TIME,t1);
   }
}

Thanks!

Object Types - OBJ_ARROW_BUY Object Types - OBJ_ARROW_SELL Any rookie question, so

Alexey Viktorov 2017.03.03 06:09 #1348

Vitaly Muzichenko:

There's a customisable fractal feature, well geez, that's awfully heavy. I've left the drawing of objects only to visually show if the fractals are forming correctly - it's not going to happen.

Question: how can I make it easier, because visual testing is stupid:

Thanks!

You can only make it easier by turning it all into an indicator. Even the comment in the upper left corner of the chart and especially the position open and close marks, which the tester itself puts, are slowing down the testing.

Getting All Available Symbols New metatrader 4 compatible Multicurrency advisor question

Andy-D 2017.03.03 08:11 #1349

Hello. Could you advise a newcomer?

Here's an example:

if(Condition1)

if(Condition2)

{

}

else

{

}

According to the code, Else should refer to if(condition1) and will be executed if condition1 is not met

But in fact it will also be executed if Condition2 is not met.

Useful features from KimIV Errors, bugs, questions HELP tradereditor

Alekseu Fedotov 2017.03.03 08:27 #1350

Andy-D:

Hello. Could you advise a newcomer?

Here's an example:

if(Condition1)

if(Condition2)

{

}

else

{

}

According to the code, Else should refer to if(condition1) and will be executed if condition1 is not met

But in fact it will be executed if Condition2 is not satisfied.

Get in the habit of putting curly braces immediately with the condition

if(Condition)

{

}

And according to your question

if(Условие1)
   {
       if(Условие2)

        {

        }
    }
   else

    {

    }

Any questions from newcomers on MQL4 and MQL5, help and discussion on algorithms and codes - page 135