Any rookie question, so as not to clutter up the forum. Professionals, don't pass by. Nowhere without you - 6. - page 855
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Hello, Task: Through an indicator.
- Place (for example - PLOT_ARROW) taking price values from a two-dimensional array.tmparray[][],
- Place (PLOT_ARROW) quantity>1 on one candle,
i.e. I can place one cross per candle (usingtmparray[]), i need more>1
Hello, Task: Through an indicator.
- Place (for example - PLOT_ARROW) taking price values from a two-dimensional array.tmparray[][],
- Place (PLOT_ARROW) quantity>1 on one candle,
i.e. I can place one cross per candle (usingtmparray[]), i need more>1
Hello, Task: Through an indicator.
- Place (for example - PLOT_ARROW) taking price values from a two-dimensional array.tmparray[][],
- Place (PLOT_ARROW) quantity>1 on one candle,
i.e. I can place one cross per candle (usingtmparray[]), i need more>1
If eight crosses on each bar is enough, then no problem, otherwise go to MQL5.
And mql4 doesn't limit the number of buffers now either.
Yes and mql4 does not limit the number of buffers now.
Please tell me how to implement it!?
I didn't give an answer to your question at all. Not even an answer, but an observation. To give you advice you need to understand what you want to get. And I don't.
If it's an indicator, then two-dimensional arrays don't apply there. If it's a simple custom array, it cannot be used as an indicator buffer. In order to get 2 indicator values on one candlestick, you should have 2 buffers, each of them should have a value that differs from each other. Otherwise, one will be hidden under the second one.
I apologise in advance to the admins for trolling, a similar question is in a separate thread https://www.mql5.com/ru/forum/154928,!))
Objective:
- Create an array of 2,000 moving average values.
- To mark with crosses, seals formed from the joined SMAs.
The result is that the crosses are scattered disordered and there is nothing.
Question:
It turns out that the error that causes the crosses to be placed in a way that does not correspond with the position of the SMA aggregate, is in the formation of the SMA array || ...?