Renter - page 23
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Mathemat:
Кстати, нуль производной функции без 1 в числителе, как ты сделал, не равен нулю производной исходной функции.
No, it's not. So?
Like, roughly equal for their derivatives.
well, it's time to conduct a numerical experiment.
What inputs do we set?
q=0.3, t=50-> k=0.0280638338 (2.81%).
The value of the derivative is -0.0014.
q=0.3, t=50-> k=0.0280638338 (2.81%).
My option:
Sergey, your option is clear. This would be a good first approximation.
Oleg, where is your answer for k - along with the check in the derivative function?
Oleg, what are you doing? How can you substitute k and alpha instead of arguments? These are qualitatively different values.
You don't need to show all the calculations, it's unnecessary. Just substitute k for the derivative you found from Sergei's function.
OK, I'll leave it for now.
Oleg, what are you doing? How can you substitute k and alpha instead of arguments? These are qualitatively different quantities.
that's right. Look at the algorithm for the calculation. Fraction of withdrawals -- you have k, I have alpha -- in the algorithm it is x.
On the graph, the x-axis changes from 0 to 1. The curve shows the total funds withdrawn at different x's.
I got a more exact solution:
Here, the exact derivative is shown in blue, the approximate derivative is shown in black (the expression for it above the graph) and kOpt is obtained for its zero!