How do you calculate the length of a line from the coordinates? - page 7
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so the points then, too.
And what's left?
of what?
---------
I understand that the pulse length is measured.
;)
And what's left?
of what?
You try doing the math yourself:
If one person is 2m tall and weighs 80kg and the other is 1.9m and weighs 90kg. Who is taller or heavier is clear, but who is bigger? :)
You try calculating it yourself:
you can calculate the length of one wavelength relative to the other like this:
dP1^2 dT1^2
sqrt(-------- + --------)
dP2^2 dT2^2
dP is the dinat on the price scale, dT accordingly on the time scale. Since it is counted in relative units, there is no adding pies to kilograms, all chikipuka.
upd drawing is crooked.
sqrt((dP1/dP2)^2+(dT1/dT2)^2)
If one person is 2m tall and weighs 80kg and the other is 1.8m and weighs 90kg. Who is taller or heavier is clear, but who is bigger? :)
You try doing the math yourself:
I don't know about the wavelengths, but in the first and second examples they are equal.
point-minutes winded up.
;)
If one person is 2m tall and weighs 80kg and the other is 1.9m and weighs 90kg. Who is taller or heavier is clear, but who is bigger? :)
That's not the case. Who is bigger is an abstract value (as opposed to length).
I don't know about the wavelengths, but in the first and second example they are equal.
Equal. How do you mathematically get that
SZZ: you might as well compare the projections on the abscissa and ordinate axes separately, it would be more correct, and there would be less noise
that's what I wrote about.
before.
About relativity.
Simply, if the waveguys are comparing hypotenuse and they are not interested in what it is called - let them compare.
Try to calculate it yourself:
Maybe set the coordinates of the rectangle
0 - bottom left corner of rectangle - 1.20(price)*1000(bar)
upper left corner of rectangle - 2,0(price)*1000(bar)
top right corner - 2.0*1
bottom right corner - 1.20*1
а1=1,30*50
а2=1,50*40
b1=a2
б2=1,30*30
и
а1=1,30*50
а2=1,50*40
b1=a2
б2=1,30*10
corrected, b1=a2