Is it possible to estimate the price? - page 6
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по окончанию периода или по достижении среднего размера
The distribution changes. At the end of one period there were so many candles of this size, so many candles of another size. And on the next candle to collect statistics again.
It is a sisyphean task.
I don't understand you... For example, it is the 20th day of the month. The area of our triangle is the same, but the average area of the triangles in the previous (for example) 6 similar periods (20 days of each of the six months) was greater. Which means that the volatility in the remaining 10 days will increase and the size of the pattern will be closer to its average.
I do not understand you... For example, it is the 20th day of the month. The area of our triangle is the same, but the average area of the triangles in the previous (for example) 6 similar periods (20 days of each of the six months) was greater. Which means that the volatility in the remaining 10 days will increase.
Someone already gave a link to "player error".
https://ru.wikipedia.org/wiki/%D0%9E%D1%88%D0%B8%D0%B1%D0%BA%D0%B0_%D0%B8%D0%B3%D1%80%D0%BE%D0%BA%D0%B0
Someone already gave a link to "player error".
I may be wrong, but I'll say it again: the ox was not analysed in this way. It's just interesting to look at such an inductor.
I may be wrong, but I repeat: the ox has not been analysed in this way. It's just interesting to look at such a turkey.
If you do it, it's a little different. Build the scales on the candlesticks and the SCO. Then there will be no problem with the calculationsRMS?
>>SCO?
RMS deviation.All this can be calculated on the fly
let's give it a try
>> let's give it a try.
See