![MQL5 - Language of trade strategies built-in the MetaTrader 5 client terminal](https://c.mql5.com/i/registerlandings/logo-2.png)
You are missing trading opportunities:
- Free trading apps
- Over 8,000 signals for copying
- Economic news for exploring financial markets
Registration
Log in
You agree to website policy and terms of use
If you do not have an account, please register
Exactly! And in your picture it is quantised. Look for the clamp.
It's a matcad, I presume? I can't say, I don't have it.
Read carefully, the difference cannot be unquantised. I.e. it would be the opposite strange if there were no quantization.
Please explain why the quantum for R(B)-R(A) should be different from the quantum for R(A) ? It seems to me that in both cases it should correspond to Point.
If we write the equality ln(Price + i * Point) = ln(Price) + k[i], then obviously the value of k[i] is not proportional to i.
If we write the equality ln(Price + i * Point) = ln(Price) + k[i], then obviously the value of k[i] is not proportional to i.
ln(Price + Point ) - ln(Price) = ln(Price) + ln(1 + Point/ Price ) - ln(Price) ≈ Point/ Price.
That is, the quantum of both R(A) and R(B) is equal to Point / Price. And for their differences for some reason visually it is an order of magnitude bigger.
ln(Price + Point) - ln(Price) = ln(Price) + ln(1 + Point/ Price ) - ln(Price) ≈ Point/ Price.
That is, the quantum of both R(A) and R(B) is equal to Point / Price. And for their differences for some reason visually it is an order of magnitude bigger.
In principle, the paradox is solved by taking each stroke as a single point. Especially since then we also get a quantum of the order of 0.0001, which is just the order of Point/Price.
The conversion to strokes is due to different Price values for different R(A). But for the corresponding R(B) Price is about the same, so there is no vertical blurring of a point into a stroke.
In short the last posts should be transferred here:).