Pure maths, physics, logic (braingames.ru): non-trade-related brain games - page 78

 
Avals: I think the point here is that if a force is applied to a small box, it will start moving with acceleration and will have variable momentum and kinetic energy. Therefore you need less force than (M+m)Kg but more than mKg
OK, mKg + eps. One has to move one box anyway. Let it be a small one.
 
TheXpert:
On a smooth surface there are two boxes connected by a spring
.
Their masses are M and m, (M > m) the coefficient of friction is K.
A constant force F acts on one of the boxes.

What minimum force F is needed and on which box to apply it to make both boxes move.


Apparently, it is required to find the minimum constant force that needs to be applied for some time. The condition is not formulated quite correctly.

Everyone who is solving - it is necessary to take into account that at the moment of the second box collapse the first box has already gained some speed (it moved accelerated, because the spring reaction force was not constant, but grew from 0), so F needed for collapse will be less than in statics. I kind of got k(m+M/2)g, I am not writing the solution yet.

Документация по MQL5: Операции с массивами / ArrayMinimum
Документация по MQL5: Операции с массивами / ArrayMinimum
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Операции с массивами / ArrayMinimum - Документация по MQL5
 

alsu:

I kind of got k(m+M/2)g, I don't write the solution yet.

Well, or k(M+m/2)g, whichever is smaller.

Ps But the former is smaller if m<M))

 
It's probably about the work that needs to be done. And work can be done by different forces.
 
Mathemat:
It's probably about the work that needs to be done.


Yes
 
Calculate what the potential energy of the second box must be at a minimum for the movement to begin
 
TheXpert:
The challenge for loonies is to solve the same problem if you can change the vector of force arbitrarily.
About that - it doesn't seem to matter. Since the work done does not depend on the trajectory of the body http://fizportal.ru/physics-book-27-4
27.4. Потенциальная энергия деформированной пружины. Закон сохранения энергии | FizPortal
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27.4. Потенциальная энергия деформированной пружины  Деформированная (например, растянутая) пружина способна совершить работу (рис. 155). рис. 155  Действительно, если к растянутой пружине прикрепить некоторое тело, то пружина будет действовать на него с некоторой силой, под действием которой тело начнет смещаться. Следовательно, будет...
 
But you can also do the equation of motion, but then, as they say, with and without integrals, and in the coordinate system))
 
Andrei seems to say that the solution is simple, but intuitively unclear.
 
Avals:
about that - it doesn't seem to matter. Since the work done does not depend on the trajectory of the body http://fizportal.ru/physics-book-27-4
What is meant is that the force may not be constant