Here is one idea:
int day = DayOfWeek(); return( day > 0 ? day-1 : 6);
And another one:
return( TimeDayOfWeek( LocalTime()-86400 )); // Substract one day (86400 secs) from current local time)
string f; switch(TimeDayOfWeek(TimeLocal()-86400)) { case 1: f="MONDAY"; break; case 2: f="TUESDAY"; break; case 3: f="WEDNESDAY"; break; case 4: f="THURSDAY"; break; case 5: f="FRIDAY"; break; case 6: f="SATURDAY"; break; case 0: f="SUNDAY"; break; } Alert(f);
drazen64: And another one:
Probably don't want to do that. -86400 (or -PERIOD_D1*60) doesn't account for weekends or market holidays.return( TimeDayOfWeek( LocalTime()-86400 )); // Substract one day (86400 secs) from current local time)
#define HR2400 (PERIOD_D1 * 60) // 86400 = 24 * 3600 int TimeOfDay(datetime when=0){ if(when == 0) when = TimeCurrent(); return( when % HR2400 ); } datetime DateOfDay(datetime when=0){ if(when == 0) when = TimeCurrent(); return( when - TimeOfDay(when) ); } //datetime Tomorrow( datetime when=0){ if(when == 0) when = TimeCurrent(); // return(DateOfDay(when) + HR2400); } datetime Yesterday(datetime when=0){ if(when == 0) when = TimeCurrent(); int iD1 = iBarShift(NULL, PERIOD_D1, DateOfDay(when) - 1); return( iTime(NULL, PERIOD_D1, iD1) ); }

You are missing trading opportunities:
- Free trading apps
- Over 8,000 signals for copying
- Economic news for exploring financial markets
Registration
Log in
You agree to website policy and terms of use
If you do not have an account, please register
I know day of week returns today https://docs.mql4.com/dateandtime/dayofweek
How do I get yesterday day of week ?