athanfx:
- I cant figure out hot to add time to "time".. is it done like mydayis=StrToTime(D '2012.01.16 14:00' )+ what? How you add time so to get on on the next day?
There are 24 hours each and every day.- I cant figure out hot to add time to "time".. is it done like mydayis=StrToTime(D '2012.01.16 14:00' )+ what? How you add time so to get on on the next day?
datetime mydayis = StrToTime(D '2012.01.16 14:00' ), tomorrow1400 = mydayis + 86400, // 24 * 60 * 60 midnight = mydayis - mydayis % 86400, tomorrow0000 = midnight + 86400, tomorrow1400also = tomorrow0000 + 50400; // 14 * 60 * 60
athanfx:
- I cant figure out hot to add time to "time".. is it done like mydayis=StrToTime(D '2012.01.16 14:00' )+ what? How you add time so to get on on the next day?
You need to read about and understand datetime variable types . . . especially here where it says . . .
"Its internal representation is a long integer number of 4 bytes. The value represents the amount of seconds elapse from 00:00 Jan 1, 1970. "
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Hi,
what I m trying to do is on a string that i m reading from a file that has a Date format to add 24 hours. So for example
I m reading '2012.01.16 14:00' to convert this on '2012.01.17 14:00' and so on. Its a CSV file from an excel so Date format is not a problem i can change it.
But I ve got problems like:
- I cant figure out hot to add time to "time".. is it done like mydayis=StrToTime(D '2012.01.16 14:00' )+ what? How you add time so to get on on the next day?
- Even bigger problem is when i m at the end of a month like '2012.01.31 14:00' and then i should convert to '2012.02.01 14:00' etc
Any code function/help on that?
Thanks
Athan