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Does this allow you to calculate the turnaround time of the channel?
Not really, or rather not at all. Every motorist(trader) needs to know at what speed on a turn the car(price) can go off the road(channel).
Not really, or rather not at all. Every motorist(trader) should know at what speed on a corner the car(price) can go off the road(channel).
Exactly! Since all curves are different and we know the average speed, the exit is fast and frequent. Alexander will confirm)))
Exactly! And since all turns are different and we know the average speed, the exit is quick and frequent. Alexander will confirm)))
As for the price flying out of the channel, in addition to speed, you need to know the real volume (analogue of mass), otherwise the problem is basically unsolvable.
Not really, or rather not at all. Every motorist(trader) should know at what speed on a corner the car(price) can go off the road(channel).
Nothing is known about the speed of the price itself, but only the speed of arrival of a new price value.
That is, if you look at the speedometer more often, it will not change the speed of the car.
Nothing is known about the speed of the price itself, only the speed of arrival of the new price value. Do not confuse the two.
That is, if you look at the speedometer more often, it will not change the speed of the car in any way.
Nothing is known is too loud a word. The speed is calculated with the margin of error of ticks arrival.
Exactly! And since all corners are different, and we know the average speed, the departure happens often and quickly. Alexander will confirm)))
You don't, and you only know the average speed of price measurements, but that doesn't say anything about the price itself and its speed.
Knowing nothing is too strong a word. The speed is calculated with the margin of error of the incoming ticks.
That's the thing, the local deity with the physics department paper doesn't calculate the speed of the price itself, and he's not interested in it at all. ))
You don't, you only know the average speed of price measurements, but that doesn't say anything about the price itself or its speed.
Better yet, average over a million ticks and you'll know everything. Everything that Alexander knows))
Waiting for the results of averaging from the scientific luminary. ))
Waiting for the results of averaging from the scientific luminary. ))