Any rookie question, so as not to clutter up the forum. Professionals, don't pass by. Nowhere without you - 6. - page 568
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The description of functions in the documentation looks cumbersome, unfamiliar, complicated.
A newcomer in many ways may not find parallels between the old textbook and the new documentation.
Maybe make a link to the old documentation or . new textbook.
I will definitely reread it.
Why don't you study the new mt4 and write a tutorial? someone has to do it!
The description of functions in the documentation looks cumbersome, unfamiliar, complicated.
A newcomer in many ways may not find parallels between the old textbook and the new documentation.
Maybe make a link to the old documentation or . new textbook.
I will definitely reread it.
Find an ancient build, there will be an ancient guide with it. What's the question? Find an ancient build, open the meta-editor and press F1 on any function.
Find the ancient build, there will be an ancient guide with it. What's the question? Find an ancient build, open the meta-editor and press F1 on any function.
The question is still the same: How do you get to the right place at the right time?
For those on the go, an off-line version of the old documentation that some good man wrote will come in handy.
Is there a handy function that returns the bar number by its time, datetime-->int ? That is, Time[int l]-->l. Thanks. Trying this, but the results seem to jump by +-1 depending on the bar...
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Attached a Zip archive.
Is there a handy function that returns the bar number by its time, datetime-->int ? That is, Time[int l]-->l. Thanks.
WouldiBarShift work?
WilliBarShift work?
Thank you! For some reason I thought the purpose of this function was different. I'll give it a try now.
Thank you! For some reason I thought the purpose of this function was different. I'll give it a try now.
Good luck!
If you know the time of the bar, this function will find its number (ugh, ugh, it hasn't failed yet). :)
you have UAC disabled
UAC in Never Notify mode
And here is the proposed solution: