[WARNING CLOSED!] Any newbie question, so as not to clutter up the forum. Professionals, don't go by. Can't go anywhere without you. - page 970

 
Vinin:

Thank you.
 
AlexSTAL:
warnings

My mother tongue is Ukrainian. But thank you for your attention.
 

Help! If I have 2 pendants set and one of them closed by Take Profit, I need the 2nd one to be deleted. How do I write it? Where is the error in the code?

int pos;
for (pos=0; pos<OrdersTotal(); pos++)
{
if (OrderSelect(pos, SELECT_BY_POS))
{
if (OrderClosePrice() >= OrderTakeProfit())
{
int i;
for (i=0; i<OrdersTotal(); i++)
{
if (OrderSelect(i, SELECT_BY_POS))
{
if (OrderDelete(OrderTicket()))
{
Print("Ордер удален");
       }
      }
     }
    }
break;
   }
  }
 }
return(0);
}
 

Good evening (I forgot to say hello in previous posts). Can you advise which function to use to do the following. In the Expert Advisor is opening an order by the indicator on the current candle (let it be number = 9). If after the opening order, it (the indicator) re-draw (and after closing candle 9 did not appear), then I need to AFTER the closing candle 9 order closed.

 

There are input parameters:

bool Mart - if true, it means there was a closed order on a stop, hence doing a doubling.

TradeInf - trade permission, if true, it means that there are no traded orders and we may trade)

There is the following code:
if (Mart == true && TradeInf==true)
{
Alert("double the lot");
LotS=NormalizeDouble(LotS*martin,2);
Alert("lot size",LotS);
}
if (Mart == false && TradeInf==true)
{
Alert("Reset lot");
LotS=lot;
}

Then in OpenOrder commands, lot size = LotS.

So if it finds a lot closed by lot, the lot size becomes -9315605757223323600
why? What's the reason?

 

Hello, I'm calculating a lot from a balance value according to a different principle...

I end up with a number like 0.2345, how do I cut double without rounding it, I mean:

to one digit - 0.2

to two digits - 0.23

to three - 0.234 and so on...

 
akacuk21:

Hello, I'm calculating a lot from a balance value according to a different principle...

I end up with a number like 0.2345, how do I cut double without rounding it, I mean:

to one digit - 0.2

to two digits - 0.23

to three - 0.234 etc...


double lot = NormalizeDouble(LOT,2)

lot - for placing orders

LOT - formula for order calculation

"2" - rounding to 2 decimal places.

 
Thanks for the answer, but in the case of NormalizeDouble, a number like 0.29 rounded to one digit will be 0.3 and I need it to be 0.2
 
It's against the rules of rounding, so let's wait to hear what the elders have to say.
 
Sys15975382:
It's against the rules of rounding, let's wait for what the older comrades have to say.

Uh... Gentlemen. You can't normalise lots like that... :) Here's a little help:

//+----------------------------------------------------------------------------+
//|  Автор    : Ким Игорь В. aka KimIV,  http://www.kimiv.ru                   |
//+----------------------------------------------------------------------------+
//|  Версия   : 16.05.2008                                                     |
//|  Описание : Возвращает нормализованное значение торгуемого лота.           |
//+----------------------------------------------------------------------------+
//|  Параметры:                                                                |
//|    lo - нормализуемое значение лота.                                       |
//|    ro - способ округления          (   False    - в меньшую,               |
//|                                        True     - в большую сторону)       |
//|    sy - наименование инструмента   ("" или NULL - текущий символ)          |
//+----------------------------------------------------------------------------+
double NormalizeLot(double lo, bool ro=False, string sy="") {
  double l, k;
  if (sy=="" || sy=="0") sy=Symbol();
  double ls=MarketInfo(sy, MODE_LOTSTEP);
  double ml=MarketInfo(sy, MODE_MINLOT);
  double mx=MarketInfo(sy, MODE_MAXLOT);

  if (ml==0) ml=0.1;
  if (mx==0) mx=100;

  if (ls>0) k=1/ls; else k=1/ml;
  if (ro) l=MathCeil(lo*k)/k; else l=MathFloor(lo*k)/k;

  if (l<ml) l=ml;
  if (l>mx) l=mx;

  return(l);
}