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What is meant by prediction accuracy?
A projection is drawn into the future. If the actual trajectory then coincides with the calculated trajectory, then the accuracy is considered high. How accurate is accurate? Well, it is elementary to compare the two graphs and use them to make some statistics, if necessary.
Well, the Fourier thing about knowing how to use Fourier is about the same as saying
is like saying of course tech analysis works, you just have to know how
how to use it.
What is meant by forecast accuracy?
A projection is drawn into the future. If the actual trajectory then coincides with the calculated trajectory, the accuracy is considered high. How accurate is accurate? Well, simply compare the two graphs and use them to make statistics if needed.
What is meant by prediction accuracy?
A projection is drawn for the future. If the actual trajectory then coincides with the calculated trajectory, then the accuracy is considered high. How accurate is accurate? Well elementary compare the two graphs and you can do some statistics on them, if necessary.
...And the slope of the linear regression and width of the channel are also different ...Entries that cross the 60 percent RMS in one direction will not be equal to entries in the other, the shoulders are different. Is this taken into account?
I cited a particular case of linear regression without envelope by RMS. In practice I use a more complex construction that takes curvature into account.
ANG3110, this is not a Fourier, most likely very heavily modified. If you had built a real Fourier, you would have the next point after the last analysed point, i.e. the 1st predicted point, coincide in value with the 1st analysed point. That is, the end would go to the beginning. This is a feature of the Fourier construction. Tell me how your indicator is built.
ANG3110, why did you remove the picture, I liked it. If you look closely at this picture, you can see the following, you have Fourier there, but as I understood, instead of the horizontal line the centre line of the channel is used. Now take a closer look, you have future values repeating the initial values of the analysed period. Am I right or not?
I'm on GPRS at home and no problems :)
ANG3110, why did you remove the picture, I liked it. If you look closely at this picture, you can see the following, you have Fourier there, but as I understood, instead of the horizontal line the centre line of the channel is used. Now take a closer look, you have future values repeating the initial values of the analysed period. Am I right or not?