Working out the RSI value of the current close[0] minus spread

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Hi

I have been trying to figure if this can be done.

For example if the current candle close[0] had and RSI value of say 39.000, is it possible to work out how much the RSI value would be if the close[0] fell by 10pips?

I have tried experimenting with little success:

double r = Close[2]-10*Point;

//display result as comment
comm=comm+"\nRSI - 10 = "+Rsi(r);

Thanks

Antony

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